What is the total kVA of three-phase loads drawing 16, 42, and 75 amps from a 240-volt panel?

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Multiple Choice

What is the total kVA of three-phase loads drawing 16, 42, and 75 amps from a 240-volt panel?

To calculate the total kVA of three-phase loads, you need to use the formula for three-phase power, which is: \[ \text{kVA} = \frac{\sqrt{3} \times V \times I}{1000} \] Where: - \( V \) is the line-to-line voltage (240 volts in this case). - \( I \) is the current in amps. Since there are three loads, you would calculate the kVA for each load and then sum them up. Here's how the calculation works: 1. For the first load drawing 16 amps: \[ \text{kVA} = \frac{\sqrt{3} \times 240 \times 16}{1000} \] \[ \approx \frac{1.732 \times 240 \times 16}{1000} \] \[ \approx \frac{8326.08}{1000} \approx 8.326 kVA \] 2. For the second load drawing 42 amps: \[ \text{kVA} = \frac{\sqrt{3} \times 240 \times 42}{1000} \] \[ \approx \frac{

To calculate the total kVA of three-phase loads, you need to use the formula for three-phase power, which is:

[ \text{kVA} = \frac{\sqrt{3} \times V \times I}{1000} ]

Where:

  • ( V ) is the line-to-line voltage (240 volts in this case).

  • ( I ) is the current in amps.

Since there are three loads, you would calculate the kVA for each load and then sum them up. Here's how the calculation works:

  1. For the first load drawing 16 amps:

[ \text{kVA} = \frac{\sqrt{3} \times 240 \times 16}{1000} ]

[ \approx \frac{1.732 \times 240 \times 16}{1000} ]

[ \approx \frac{8326.08}{1000} \approx 8.326 kVA ]

  1. For the second load drawing 42 amps:

[ \text{kVA} = \frac{\sqrt{3} \times 240 \times 42}{1000} ]

[ \approx \frac{

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