In a 60 Hz circuit with a 1.3 mH inductor, what is the inductive reactance in ohms after conversion?

Study for the Independent Electrical Contractors (IEC) Year 2 Part 3 Test. Use flashcards and multiple choice questions with hints and explanations to prepare confidently. Get exam-ready now!

Multiple Choice

In a 60 Hz circuit with a 1.3 mH inductor, what is the inductive reactance in ohms after conversion?

To determine the inductive reactance of a circuit, you use the formula: \[ X_L = 2 \pi f L \] where: - \( X_L \) is the inductive reactance in ohms, - \( f \) is the frequency in hertz (Hz), - \( L \) is the inductance in henries (H). In this case, we are working with a frequency of 60 Hz and an inductance of 1.3 mH (which is equal to 0.0013 H). Plugging in the values: 1. First, convert the inductance from millihenries to henries: \[ L = 1.3 \, \text{mH} = 1.3 \times 10^{-3} \, \text{H} \] 2. Substitute the values into the formula: \[ X_L = 2 \pi (60)(1.3 \times 10^{-3}) \] 3. Calculate: \[ X_L = 2 \pi (60) (0.0013) \] \[ X_L = 2 \times 3.14159 \times

To determine the inductive reactance of a circuit, you use the formula:

[ X_L = 2 \pi f L ]

where:

  • ( X_L ) is the inductive reactance in ohms,

  • ( f ) is the frequency in hertz (Hz),

  • ( L ) is the inductance in henries (H).

In this case, we are working with a frequency of 60 Hz and an inductance of 1.3 mH (which is equal to 0.0013 H). Plugging in the values:

  1. First, convert the inductance from millihenries to henries:

[ L = 1.3 , \text{mH} = 1.3 \times 10^{-3} , \text{H} ]

  1. Substitute the values into the formula:

[ X_L = 2 \pi (60)(1.3 \times 10^{-3}) ]

  1. Calculate:

[ X_L = 2 \pi (60) (0.0013) ]

[ X_L = 2 \times 3.14159 \times

More practice questions