If a 3Ø motor has a nameplate rating of 60 KVA at 240 volts, how many amps will a meter indicate?

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Multiple Choice

If a 3Ø motor has a nameplate rating of 60 KVA at 240 volts, how many amps will a meter indicate?

To determine the number of amps that a 3-phase motor will draw based on its nameplate rating, you can use the formula for calculating amperage in 3-phase systems: \[ \text{Amps} = \frac{\text{KVA} \times 1000}{\sqrt{3} \times \text{Voltage}} \] In this case, the motor has a rating of 60 KVA at 240 volts. 1. First, convert the KVA rating to watts: \[ 60 \text{ KVA} = 60,000 \text{ watts} \] 2. Next, apply the numbers to the formula: \[ \text{Amps} = \frac{60,000}{\sqrt{3} \times 240} \] 3. The square root of 3 is approximately 1.732, therefore: \[ \sqrt{3} \times 240 \approx 1.732 \times 240 \approx 415.68 \] 4. Now divide the wattage by this value to find the current: \[ \text{Amps} = \frac{60,000}{415.68

To determine the number of amps that a 3-phase motor will draw based on its nameplate rating, you can use the formula for calculating amperage in 3-phase systems:

[ \text{Amps} = \frac{\text{KVA} \times 1000}{\sqrt{3} \times \text{Voltage}} ]

In this case, the motor has a rating of 60 KVA at 240 volts.

  1. First, convert the KVA rating to watts:

[ 60 \text{ KVA} = 60,000 \text{ watts} ]

  1. Next, apply the numbers to the formula:

[ \text{Amps} = \frac{60,000}{\sqrt{3} \times 240} ]

  1. The square root of 3 is approximately 1.732, therefore:

[ \sqrt{3} \times 240 \approx 1.732 \times 240 \approx 415.68 ]

  1. Now divide the wattage by this value to find the current:

[ \text{Amps} = \frac{60,000}{415.68

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