If a 25 kVA transformer with 120/240-volt secondary windings is connected to a 240-volt load, what is the maximum amps it can deliver?

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To determine the maximum current that a 25 kVA transformer can deliver to a 240-volt load, we begin by using the formula for converting kVA to amps. The formula is:

[

I = \frac{P}{V}

]

Where:

• ( I ) is the current in amps,

• ( P ) is the power in kVA (25 kVA in this case), and

• ( V ) is the voltage in volts (240 V for the load).

First, convert 25 kVA to watts, as 1 kVA is equivalent to 1000 watts:

[

P = 25 , \text{kVA} \times 1000 , \text{W/kVA} = 25000 , \text{W}

]

Now plug in the values into the formula:

[

I = \frac{25000 , \text{W}}{240 , \text{V}}

]

Calculating this gives:

[

I = 104.17 , \text{A}

]

Since the question asks for the maximum amps the transformer can deliver, we round this value down to the nearest whole